- COMMA MEANS AND IN THIS CONTEXT
Joint probility distro p(x,y)
- 2 discrete rand vars [[stats_ch4_notes Discrete Random Variablrs#Discrete Random Variablrs dpqr#Defitions Random Vs Discrete Random Vs Continous Random]]
- gives p(x,y) for all combos of x & y, rem prob must equate to 1 (sum of all poss)
What I should be able to do given table below”:
- AND OR GIVEN MARGINAL
- p(y=1,x=2?) = sum
| \ | 1 | 2 | 3 | 4 |
|---|---|---|---|---|
| 0 | 0 | .10 | .20 | .10 |
| 1 | .03 | .07 | .10 | .05 |
| 2 | .05 | .10 | .05 | 0 |
| 3 | 0 | .10 | .05 | 0 |
Joint Prob
Joint Marginal prob aka
- slide 9/10
Varience of can be denoted like so:
Joint density func example, An easy double integral;\
Suppose the joint density function for two continuous random variables, and , is given by
Determine the value of the constant .
Solution:
- We note the inequalities btwn 0&1
- Using our given function, we can generate a graph with it, where
- only cx generates some output, and all other places generate a 0 (via area, so generate some triangle with 2 lines)
- Now that we have the shape, we can integrate the triangle, where we know that the area must equal 1 (since it rep total prob space)
- Hence, we can just integrate the double integral easily.. (recall triangles)
- Note we must generate the correct picture!
A graph of traces a three-dimensional, wedge-shaped figure over the unit square ( and ) in the (, )-plane, as shown in Figure 6.1. The value of is chosen so that satisfies the property
Performing this integration yields
Covarience Defition (p30)
Cumlative distro func:
See ex 6.15 (in exam!)
Then we plot normally (p func) and density (d func). We denote this by using the
plot()